Back when our high school physics class was learning about elastic and inelastic collisions with the conservation of momentum, I noticed that a disproportionate number of the practice problems we were assigned that had to do with elastic collisions involved steel. Obviously, when we think of steel we think of its “hardness.” It is used in a lot of heavy-duty construction, after all.
Carboxylic Acids (or organic acids) are, as their name implies, acids! I never even gave them a second thought until I came across a section in the Chemistry textbook I’m reading that provided an analysis of why they were acidic. I found it quite fascinating and I hope you do as well.
If we look at the carboxylic group:
The additional doubly-bonded oxygen atom is very electronegative and will attract the electrons that are shared in the OH bond, which further polarizes the bond and thus makes the H easier to “pop off.”
After the H detaches from the carboxyl group, it becomes of carboxylate ion, which is negatively charged. The two oxygens then form resonance structures, which stabilizes the anion and “distributes” the negative charge to a greater volume, effectively decreasing the charge density. With the diminished charge density it it less likely to grab a hydrogen from water.
For those of you that may be wondering, the first reason I cited is due to a phenomenon called electron drift.
I don’t know if it was just me, but when I was learning about the quantum orbitals and electron configurations, I never could find a complete list of the different rules to keep in mind. Additionally, they were worded in the most indirect language imaginable. Were they trying to confuse people? Here, I’ll try to clear up some of that confusion.
When filling electrons in orbitals, always fill from the lowest energy level to the higher energy levels. This means to fill then then then and so on. Because of the Aufbau Principle, Chlorine’s electron configuration is and not something like .
If you ask why this is true? Well it seems that all things in nature like to be in its least energy state, so why hold an electron way out where it’s highly energetic when you have space in the “ground level” so to speak?
A notable exception is when you have excited electrons. These electrons will seemingly “jump” into a higher energy level and violate the Aufbau Principle, but all you have to keep in mind is that the atom is not in its ground state and you’ll be okay.
Electrons want to be as spread out as possible to minimize electron-election repulsion. Thus, fill one electron in each orbital first and then come back to fill the second orbital. Again, this should be rather intuitive after introduced. This of electrons as living, breathing creatures! I don’t know anybody who would rather be cramped in a small space when there are clearly other open spaces available!
Pauli Exclusion Principle
No two electrons can have the exact same four quantum numbers and live in the same “address” or place in the atom. The closest you can get is having the first 3 quantum numbers the same, but then the last number, the spin, must be different.
As we may already know, galvanic cells are simply experimental setups that take advantage of the electron transfer during a redox reaction to do electrical work. It may be quite easy to grasp that idea that electrons flow from the anode to the cathode, but the salt bridge is a little less easy to understand.
Oversimplified Intuitive Answer
For any of you out there that are just looking for an easy way to remember that you need a salt bridge for any galvanic cell to function properly, something you can remember is that the salt bridge simply completes the circuit. It provides that “return route” for electrical charge to travel back into the anode.
A Chemistry-Based Answer
Chemistry textbooks often say that a salt bridge is necessary to “balance out the charges in the two half-cells” but what does this really mean? Let us look at the basic set-up of a galvanic cell again.
As the redox reaction occurs, electrons migrate from the anode to the cathode. In our specific case with as our anode, as the reaction carries on, more and more is formed. The net result is that the left half-cell becomes more and more positive. You can think of this in two ways:
Electrons are being taken out of the left side, and so the left side becomes more positive by virtue of subtracting negative entities.
is being formed on the left side and because they are cations, it becomes more positive.
Similarly, but in the exact opposite way, on the right half-cell is reduced to . The net result is that the right side becomes more and more negative. Again, you can think of this in two ways:
Electrons are being added to the right side, and because we are adding negative-charged particles the right half-cell must become more negative.
(positive) is becoming (neutral) and so we are losing positive charge on the right, and thus becoming more negative.
By virtue of the left half-cell becoming positive and the right half-cell becoming negative, the electrons would be less inclined to move from the anode to the cathode. After all, why would a negative particle spontaneously move from something that is positive to something that is negative?
This is precisely where the salt bridge kicks in. The salt bridge contains both cations and anions (in our case ) that can enter either side as the reaction progress continues. Because the left half-cell becomes more positive, anions (negative) from the salt bridge will migrate there. The opposite occurs in the right half-cell. Given , the will be attracted to the positive left half-cell and the will be attracted to the negative right half-cell.
Understanding this fact will help you grasp the textbook wording of “balancing out the charges in the two half-cells.” It helps keep the left side negative and the right side positive… for the happiest of balances!